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Secure https//session.masteringphysics.com/myct/itemView?assignmentProblemiD-89546500 HW 1 CH 21 Exercise 21.33 11 A.cp Constants A point charge is at the origin. With this point charge as the source point, what is the unit vector r in the direction of (a) the field point at z = 0 -1.35m (b) the field point at r 12 0cm, y 12.0 cm, (c) the field point at z =-110m, y-260m? Express your results in terms of the unit vectors i and j Submit Request Answer Part B Express your answer in terms of the unit vectors i and j. cise Submit ercis Part C Express your answer in terms of the unit vectors i and j. xercis ck Submit ster NEWTO right 20 l Notice Provide Feedback

Explanation / Answer

let a = (0,0) be the origin and b = (x,y) be the other point

then the vector from a to b is v = b - a = (x,y) - (0,0) = <x,y>

to get the unit vector you divide <x,y> by it's modulus

|x,y| = sqrt( x^2 + y^2)

so r = <x,y> / |x,y|

a)

v = <0,-1.35> and |v| = sqrt( 0^2 + (-1.35)^2) =1.35

so r = <0,-1.35> / 1.35

r = <0,-1>

r = -1j

b)

v = <12,12> and |v| = sqrt( 12^2 + 12^2) =12*sqrt(2)

so r = <12,12> / 12*sqrt(2)

r = < 1/sqrt(2) , 1/sqrt(2) >

r = 1/sqrt(2) i +1/sqrt(2) j

c)

v = <-1.1,2.6> and |v| = sqrt( 1.1^2 + 2.6^2) = sqrt(7.97)

so r = <1.1,2.6> / sqrt(7.97)

r = < 1.1/sqrt(7.97), 2.6/sqrt(7.97) >

r = 1.1/sqrt(7.97) i + 2.6/sqrt(7.97) j

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