. C0@ www webasagnetweb.St 17538384·Q25 My Notes Ask Your Teacher 23. 44 points

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. C0@ www webasagnetweb.St 17538384·Q25 My Notes Ask Your Teacher 23. 44 points | Previous Answers CJ10 22 TB.005 A 1.2 kg rod that has a length of 1.0 m and a resistance of 5.0 slides with constant speed down a pair of frictionless bottom. Other than the rod, the rest of the circuit is resistanceless. A uniform magnetic field of mag rails as shown. Determine the speed of the rod. magnitude 3.0 T is perpendicular to the plane formed by the rod and the 0.38 m/s 2.6 m/s 0.90 m/s 8.7 m/s -6.5 m/s Additional Materials uSection 221

Explanation / Answer

Force on the rod due to magnetic field:

F=i*L*B

iLB=mg (as it is moving with constant velocity so net force=0 upward force magnitude=downward force magnitude)

1.2*9.8=i*1*3

i=3.92 ampere

Induced emf =i*R=Bvl

3.92*5=3*v*1

v=6.53 m/sec

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