. At one position and time, an em wave field magnitude of 1.99 mT. Calculate its
ID: 2029535 • Letter: #
Question
. At one position and time, an em wave field magnitude of 1.99 mT. Calculate its wave speed. in an insulator has an electric hield magnitude of 311 kVm and a magnetic xes wi SOLUTION em wave moving in vacuum perpendicular to a perfectly reftlecting surface exerts a radiation of 518 Pa on that surface. Find the intensity of that em wave EQUATION USED (ONE SIGN) SOLUTION ANSWER 3. At one position and time, the electric tield of an em wave in vacuum is 7.65 MV/m toward the top (f) and its magnetic field is 25.5 mI out of the paper (O). Find the corresponding Poynting vector. ANSWER Here I use --in calculating the magnitude. MAGNITUDE DIRECTION 4. A linearly-polarized em wave of intensity 246 MW/m2 moves through (nonmagnetic) zircon, which hasa permittivity of 3,27 x 10-11 Fim for this em wave. Find the electric field amplitude of this em wave. EQUATION USED (ONE-SIGN) SOLUTION ANSWER 18 m/s. (Thus, you are moving apart at 47 m/s.) The speed of sound is 342 m/s. The you a slow truck, traveling south a is blasting a horn that L and S velhowing the at hear to be at 122 Hz. Find the frequency that the truck driver hears from herhorn. (You should complete the sketch, writing L. in one O and S in the other O. Then draw an tive (+) direction. Finally, add two arrows (with signed numbers) showing the numbers) showing the L and S velocity components.) SOLUTION ANSWER The truck driver has no speed relative to her horn, so she hearsf (Fill in the subscript.) ONE EQUATION USED u O you truckExplanation / Answer
1)
Given:
E = 311 kV/m = 311,000 V/m
B = 1.99 mT = 0.00199 T
Velocity of light is equal to the ratio of magnitude of electric field vector and the magnitude of magnetic field vector
Thus:
v = E/B
= 311000/0.00199
= 1.56 x 108 m/s
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