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Two large rectangular sheets of charge of side L are separated by a distance d (

ID: 1872986 • Letter: T

Question

Two large rectangular sheets of charge of side L are separated by a distance d (d << L). The left and right sheets have surface charge densities of 2.5 C/m2 and -15.8 C/m2, respectively. Take +x to be to the right. Randomized Variables 1 = 2.5 C/m2 2 = -15.8 C/m2 25% Part (a) Enter the value of the electric field, in newtons per coulomb, at point A. Assume point A is 0.1 d from the surface of the left sheet.

(b) Enter the value of the electric field, in newtons per coulomb, at point B. Assume point B is 0.25 d from the surface of the left sheet.

(c) Enter the value of the electric field, in newtons per coulomb, at point C. Assume point C is 0.5 d from the surface of the left sheet.

(d) Enter the value of the electric field, in newtons per coulomb, at point D. Assume point D is 0.1 d from the surface of the right sheet.

Explanation / Answer

ANS)

electric field due to a large charged sheet of surface charge density sigma is given by

E=sigma/(2*epsilon)

and the field is directed away from the sheet if charge is positive and field is directed towards the sheet if charge is negative.

part a:

at point A, field due to positively charged sheet is along -ve x axis.

field due to negatively charged sheet is towards +ve x axis.

total field=(15.8*10^(-6)/(2*8.85*10^(-12)))-(2.5*10^(-6)/(2*8.85*10^(-12)))

=ANS CALCULATE YOURSELF N/C

the negative sign indicates field is along -ve x axis.

part b:

at point B, field due to +ve sheet is towards +ve x axis and field due to -ve sheet towards +ve x axis

so total field=(15.8*10^(-6)/(2*8.85*10^(-12)))+(2.5*10^(-6)/(2*8.85*10^(-12)))=ANS N/C

part c:

at point C, field due to +ve sheet is towards +ve x axis and field due to -ve sheet towards +ve x axis

so total field=(15.8*10^(-6)/(2*8.85*10^(-12)))+(2.5*10^(-6)/(2*8.85*10^(-12)))=ANS N/C

part d:

at point D, field due to +ve sheet is towards +ve x axis and field due to -ve sheet towards -ve x axis

so total field=-(15.8*10^(-6)/(2*8.85*10^(-12)))+(2.5*10^(-6)/(2*8.85*10^(-12)))=ANS N/C

PLZ CALCULATE ANSWERS YOURSELF

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