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4. Place a textbook on the bag and quickly measure water level of the two sides

ID: 1872697 • Letter: 4

Question

4. Place a textbook on the bag and quickly measure water level of the two sides of the manometer, Subtract them to get the net height h of the water Left side- Right side h2.5cm cm esun ho lanahnea Lengh L-22 wih om Calculate the mass of the textbook and masses using this formula, remembering Density of Water 1 gm/em (See book photos above.) Mass =hs (1 m) Calculated Book Mass- grams cm Mesurod Book mass 7. Use the scales provided and weigh textbook Calculated Mass-Measured Mass Measured Mass % error of difference= x100% % error of difference- 8. Repeat the experiment by using the small bag. Put your textbook directly on bag and adjust the amount of air so the book just makes even contact with bag. Quickly measure the water level of the two sides of the manometer Subtract them to get the net height h of the water Left side - Right side- cm cm cm 9. Measure the length L and the width W in cm of the area of the book that is in mutual contact with air bag. length = width = cm area cma cm 10. Calculate the weight of book using this formula remembering Density of Water 1 gm/cm Mass-hs( 1gm cm )«A Calculated Book Massgrams Use one of the scales provided and weigh the textbook Book mass grams 11. Book Mass - Book Mass x100% % error of difference "

Explanation / Answer

6. from 4 and 5

given

left side level in manometer, l = 6 cm

right side level in manometer, r = 3.5 cm

hence height difference h = 2.5 cm

length L = 22 cm

width, W = 10.4 cm

area = LW = 228.8 cm^2

hence

Mass = h*A = 2.5*228.8 = 572 g

now for measured book mass m

7. %error = |572 - m|*100/m

whwere m is in grams

Questions

1. to find weight of the car

there are four wheels of each car, we can calculate the normal reaction force on four wheels and then calculate mass form the previous formula

but we need the surface area of contact with the ground, which is difficult to know

instead we can have for a tyre

internal pressure P

then A = N/P ( where N is the normal reaction force)

and for four tyres N1 + N2 + N3 + N4 = W ( W is weight of the car)

2. even if the gravity of earth was smaller, the mass of the meausred object will remain the same as this changes the weight of the object only

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