part a and b please Assignment 5 Begin Date: 2/9/2018 1:30:00 PM -- Due Date: 2/
ID: 1872573 • Letter: P
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part a and b please
Assignment 5 Begin Date: 2/9/2018 1:30:00 PM -- Due Date: 2/16/2018 12:30:00 PM End Date: 2/16/2018 12:30:00 PM (696) Problem 6: Two children pull a third child backward on a snow saucer sled exerting forces F1 = 8.5 and F2 = 7.5 as shown in the figure. Note that the direction of the friction force f= 5.3 N is unspecified: it will be opposite in direction to the sum of thc othcr two forccs 45 Free-body diagram Otheexpertta.com 50% Part (a) Find the magnitude of the acceleration of the 45 kg sled and child system, in meters per second squared Grade Summary Deductions Potential a= 0.3051 15% 85% 78 9 HOME sin cotan a atan0acotan cos) asin) tan() | | ( acos) Submissions Attempts remaining: 7 % per attempt) detailed view ) sinh0 cosh)tanh) cotanhO DegreesRadians 4% 4% 4% END BACKSPACE | 13H.1 CLEAR Submit Hint I give up! Hints: 1 for a 3% deduction. Hints remaining: 1 Feedback: 4% deduction per feedback Draw your own free diagram for a sled, complete with an appropriate system of coordinates. Find the magnitude of the pulling force Submission Historv Answer Hints Feedhaclk Totals 3% 0% 0% 3% 4% 0% Draw your own free diagran for a sled, complete with an appropriate system of coordinates. Find the magnitude of the pulling force 7% 0.208 a= 0.299 4% 0% 4% a= 4% 0% 4% 0.305 Totals 12% 0% 15% 50% Part (b) Assuming the sled starts at rest, find the direction of the sled and child system in degrees north of east All content © 2018 Expert TA, LICExplanation / Answer
(A) F = F1 + F2
= 8.5 (cos45i + sin45j) + 7.5 (cos30 i - sin30 j )
= 12.5 i + 2.26 j
|F| = sqrt(12.5^2 + 2.26^2) = 12.7 N
direction = tan^-1(2.26 / 12.5) = 10.25 deg
Fnet = 12.7 - 5.3 = 7.4 N
a = Fnet / m = 0.164 m/s^2 .....Ans
(B) theta = 10.25 deg ...Ans
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