part A An object whose height is 3.6 cm is at a distance of 8.5 cm from a spheri

Question

part A An object whose height is 3.6 cm is at a distance of 8.5 cm from a spherical concave mirror. Its image is real and has a height of 11.6 cm. Calculate the radius of curvature of the mirror.
(in cm) 1.30101 cm

part B How far from the mirror is it necessary to place the above object in order to have a virtual image with a height of 11.6 cm?
(in cm)

You are correct.
Your receipt no. is 169-4434

part A An object whose height is 3.6 cm is at a distance of 8.5 cm from a spherical concave mirror. Its image is real and has a height of 11.6 cm. Calculate the radius of curvature of the mirror. (in cm) 1.30 1/2 10^1 cm You are correct. Your receipt no. is 169-4434 Help: Receipt part B How far from the mirror is it necessary to place the above object in order to have a virtual image with a height of 11.6 cm? (in cm) You have to combine the mirror equation (which includes f,d_o and d_i) with the equation for the magnification (h_o,h_i,d_o,d_i). You know h_o,h_i and f. d_i and d_o are unknown. Then you can solve the two equations with two unknowns. Remember that the image distance is negative. CAN SOME ONE HELP GET THIS PART I COULD NOT FIGURE OUT DID ANY ONE KNOW HOW TO SOLVE IT.

Explanation / Answer

Part B

Magnification = h_i / h_o = -11.6/3.6 = d_i / d_o => d_i = (-11.6/3.6) d_o

1/d_o + 1/d_i = 2/R

1/d_o + (-3.6/11.6)/d_o = 2/13

(11.6-3.6)/11.6 d_o = 2/13, d_o = 4.482 => d_i = 14.444 object should be placed 4.482cm far from the mirror to have 11.6 cm tall virtual image

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