Part A An electron moving with a speed of 4.2x105 m/s in the positive direction

Question

Part A An electron moving with a speed of 4.2x105 m/s in the positive direction experiences zero magnetic force. When it moves in the positive y direction, it experiences a force of 3.6x10-13 N that points in the positive z direction. What is the direction of the magnetic field? o- SubmitP Previous AnswersRequest Answer X Incorrect; Try Again; 5 attempts remaining Part B What is the magnitude of the magnetic field? Express your answer using two significant figures. B= 5.4 T Previous Answers Correct

Explanation / Answer

F = q*(vXB)

v is in +y direction

F is in +z direction

q is negative

For F to be in +z and q being negative:

vXB should be in -z direction

since V is in +y direction and vXB is in -z, B must be in +x direction

Answer: x

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