Part A An electron of mass 9.11x10-31 kg leaves one end of a TV picture tube wit

Question

Part A An electron of mass 9.11x10-31 kg leaves one end of a TV picture tube with zero initial speed and travels in a streight line to he accelerating grid, which is a distance 2.80 cm away. It reaches the grid with a speed of 3.20x106 m/s. The accelerating force is constant. Find the acceleration. 11.83x10|4 m/s2 Submit My Answers Give Up Incorrect; Try Again; 3 attempts remaining The correct answer does not depend on: z10. Part B Find the time to reach the grid Submit My Answers Give Up Part C Find the net force. (You can ignore the gravitational force on the electron). Submit My Answers Give Up

Explanation / Answer

a] By using,

v^2 = u^2 + 2as

v^2 = 0 + 2as

a = v^2/2s

= (3.20*10^6)^2/(2*0.028)

= 1.83*10^14 m/s^2

b] By using,

v = u + at

v = 0 + at

t = v/a

= 3.20*10^6/(1.83*10^14)

= 1.75 * 10^-8 s

c] F = ma

= 9.11*10^-31*1.83*10^14

= 1.67*10^-16 N answer

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