2. A large flat cylinder of constant charge density --5.5 x 10 7 Crn 3 is shown

Question

2. A large flat cylinder of constant charge density --5.5 x 10 7 Crn 3 is shown in Fig. I. This cylinder has a radius of more than 5 m and a thickness of 3.0 cm. Its top and bottom surfaces are perpendicular to the z direction. To provide a reference point, the center of the cylinder is labeled as "" 3.0 _radius> 5 m A cross section of the cylinder through "e" is shown in Fig. 2. What is the electric field at the position inside the cylinder marked "w", which is 1.0 cm below point "e" Since the distances indicated in Fig. 2 are much smaller than the radius of the cylinder, you can make the simplifying approximation in your calculation that the cylinder has an infinitely large radius. Fig. 2 3.0 cm 1.0 cm The cylinder continues in this direction, but its picture is cut off here due to lack of space. The cylinder continues in this direction, but its picture is cut off here due to lack of space. One more problem on reverse side)orsna

Explanation / Answer

given
volume charge density , rho = -5.5*10^-7 C/m^3

now from the given configuration
to find electric field at point w
consider a cylinderical gaussean surface of thickness 2 cm, coaxial with the given cylinder

then as radius is very large this can be considered as a infinite thick plate electric field at point w
hence

from gauss law
E*pi*r^2*2 = q/epsilon
q = rho*pi*r^2*d
hence
E = rho*pi*r^2*d/pi*r^2*2*epsilon
E = rho*d/2*epsilon

now d = 2 cm
hence
E = -5.5*10^-7*0.02/2*epsilon
E = 620.6530 N/C

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.