0.447 m/s )-71.5 m/s Convert units of speed and acceleration to SI. vo = ( 1.60%
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0.447 m/s )-71.5 m/s Convert units of speed and acceleration to SI. vo = ( 1.60% 102 mi/h 1.00 mi/h (mi/h)/s)0,447 m/s 1.00 mi/h 2 a = (-10.0 (mi/h)/s) Taking a = 0, vo = 71.5 m/s, and t = 1.00 s, find the displacement while the plane is coasting. Axcoasting - ot2 -(71.5 m/s)(1.00 s) 0 2 = 71.5 m v2 = v02 +2adxbraking Use the time-independent kinematic equation to find the displacement while the plane is braking 2 0- (71.5 m/s) Take a - -4.47 m/s* and vo-71.5 m/s. The negative sign on a mean:s that the plane is slowing down. braking 2a 4.47 m/s2) = 572 m Sum the two results to find the total 71.5 m 572 m = 644 m displacement. LEARN MORE REMARKS To find the displacement while braking, we could have used the two kinematics equations involving time, namely, x = vot +-3t2 and v = vo + at, but because we weren't interested in time, the time-independent equation was easier to use. QUESTION By how much would the answer change if the plane coasted for 2.0 s before the pilot applied the brakes? 2Explanation / Answer
According to the concept of the motion in one dimensional
Given that
Initial velocity u=71.5 m/s
Acceleration a=-4.47 m/s^2
Now we find the distance plane coasted horizontally
In this the acceleration is equal to zero
Xcoasting=ut=71.5*2=143 m
Now we find the distance after breaks applied
V^2-u^2=2aX
0^2-71.5^2=2*-4.47*X
X=571.8 m
The total net displacement =143+572=712.m
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