013 (part 1 of 2) 10.0 points The electric field near the surface of the eart po

Question

013 (part 1 of 2) 10.0 points The electric field near the surface of the eart points downward and has a magnitude 200 N/C Compare the upward electric force on electron with the downward gravitation force: 1.e., what is the ratio ? The el mentary charge is 1.6 × 10-19 C and the ma of an electron is 9.11 × 10 kg 31 014 (part 2 of 2) 10.0 points What is the magnitude of the charge th: should be placed on a coin of mass 4.2 g that the electric force balances the weight the coin near the earth's surface? Answer in units ofC

Explanation / Answer

13)Electric field = 200 N/C

Charge = 1.6*10-19 C

Mass = 9.11*10-31 kg

Electric force = 1.6*10-19*200=3.2*10-17 N

Grvitational force= 9.11*10-31*9.8=8.9278*10-30 N

Electric foelrce/gravity force = 3.2*10-17 / 8.9278*10-30 = 3.58*1012

14)Let the charge required be q

200*q = 0.0042*9.8

q=0.0042*9.8/200=2.058*10-4 C

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