1 The seme sesting deta fo an alumimum alloy is shown below %tte har sin Eris in

Question

1 The seme sesting deta fo an alumimum alloy is shown below %tte har sin Eris in the plot has wo scalies, the sop and the bottom scalies belong to the top and the botiom cunves, respectively (ksi) 5 70 6) 50 40 20 10 0 0 014 006 0.12 0.16 10.20 0.24 The eiastic moduius of the material is (103) ksi. 30 The modulus ofresilience of the material is psi. 1o he amount of enerzy a specimen that is 15 in. in length and 1 in. in dia ing senoile testing without permanent deformation is ksi. 1 B0236 C)0.287 D0.314 E0.393 B) 20 C) 40 D) 100 E) 500 B) 20 C) 40 D) 100 E) 500 tenlile force of 35 kips is applied to a specimen that is 15 in. in len e, the approximate increase in gauge length after it is unloaded is 13 )0.38 C)064 D)0.96 E)1.91 one of the following statements regarding a stress-strain curve ) The necking region happens between yield point and ultimat B) The elastic limit is the point at which elongation takes place ich additional kad C) The modulus of resilience represents the energy a material

Explanation / Answer

1.elasticity=stress/ strain

E=40/.08=500 hence ans is option E

2.modulus of resilence= 1/2*stress*strain=1/2*40*1000*.(.08/100)=16...near by ans is 20psi hence option B is correct..

5.correct ans is C...

REMAINING QUSTION IS LITTLE BIT LESS VISIBLE AND TAKE PHOTO AT CORRECT ANGLE AND AGAIN POST..THANKS

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