3.10. During a test of kinetics of an enzyme-catalyzed reaction, the following d

Question

3.10. During a test of kinetics of an enzyme-catalyzed reaction, the following data e following data were recorded: Eo (g/l) T(°C) l(mmol/ml) S(mmol/ml) V(mmol/ml-min) 30 30 30 2.63 1.92 1.47 0.96 0.56 5.13 3.70 1.89 1.43 1.11 1.64 0.90 0.58 1.33 0.80 0.57 0.033 0.02 0.01 0.005 1.6 30 49.6 49.6 49.6 49.6 49.6 1.6 1.6 1.6 0.033 0.01 0.0067 0.005 1.6 0.92 0.92 0.92 0.92 0.92 0.92 30 30 30 30 0.02 0.01 0.6 0.6 0.6 0.033 0.02 a. Determine the Michaelis- Menten constant for the reaction with no inhibitor present b. Determine the maximum velocity of the uninhibited reaction at 30°C and an enzyme inhibitor is being at 30°C and at 49.6°C. concentration of 1.6 gl. c. Determine the Ki for the inhibitor at 30°C and decide what type of used

Explanation / Answer

Answer

Enzyme catalyze reaction

V= Vmax [S]/Km [S]

rearrange the equation

1/V = 1/Vmax + Km/Vmax *1/[S]

Then if we plot a graph between 1/V and 1/[S] the y-intercept = 1/Vmax

So,Now plot a graph at T= 300

then y-intercept =0.3035

therefore, Vmax = 1/0.3035 = 3.29 mmols/min and Km= 0.025095

For the T= 49.6

therefore, Vmax = 1/0.20 = 5 and Km= 0.00253

S(mmol/ml) V(mmol/ml-min) 1/S 1/V 0.1 2.63 10 0.380228 0.033 1.92 30.30303 0.520833 0.02 1.47 50 0.680272 0.01 0.96 100 1.041667 0.005 0.56 200 1.785714

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