homeStudent: mo Class Management I Help HW-06 (Ch-22) Begin Date: 7/1/2018 12:01

Question

homeStudent: mo Class Management I Help HW-06 (Ch-22) Begin Date: 7/1/2018 12:01:00 AM- (10%) Problem 10: Assume that inside a motor 29 A moves through a 250 turn circular loop that is 11 cm in radius. Due Date: 7/22/2018 11:59:00 PM End Date: 7/29/2018 11:59:0 p à What is the magnetic field strength generated at its center in T? sin() | cos() | tan() cotan) asinacosO atan0 acotan0 sinh) coshO tanhOcotanh0 e Degrees Radians ?| (m)| 7| 8| 9 1 0 Submit Hint I give up Hids:-)% deduction per hint. Hints remaining: 2 Feedback: 0%, deduction per feedback.

Explanation / Answer

Here ,

N = 250

r = 0.11 m

I = 29 A

magnetic field = u0 * N * I/(2R)

magnetic field = 4pi *10^-7 * 250 * 29/(2 * 0.11)

magnetic field = 0.0414 T

the magnetic field at the center of loop is 0.0414 T

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.