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home / study / science / physics / physics questions and answers / In The ClassicHunter And The Moneky Demonstration, The Hunter Is A Distance, D, From The Base ... Your question has been answered Let us know if you got a helpful answer. Rate this answer Question: In the classicHunter and the Moneky demonstration, the hunter is a distance, d, from the base of ... In the classicHunter and the Moneky demonstration, the hunter is a distance, d, from the base of a tree in which a monkey is hanging a distance, h, above the hunter. The hunter is aiming directly at the monkey and fires his gun. The initial velocity of the bullet, Vo, makes an angle with the horizontal. Set the coordinates axes with an orgin at the point where the bullet leaves the muzzle of the gun, positive y in the upwards direction and postiive x in the direction toward the tree. The monkey releases his grip and starts to fall at exactly the same time as the bullet leaves the muzzle of the gun.

a). What must the velocity of the bullet be greater than or equal to in order for the bullet to always hit the monkey? (Answer will be an inequaility in terms of Vo, d, h, g, and angle)

b). Use your result from question 2 to determine the minimum velocity of the bullet to hit the monkey if h=10 m and d = 20 m

c). Under what condition will the bullet hit the monkey for any initial velocity of the bullet greater than or equal to zero?

Explanation / Answer

monkey is at height h form the ground

the hunter is at distance d form the base of the tree

initial velocity of bullet = vo

angle with horizontal = theta

the monkey drops at the same instant the gun is fired

a. for the bullet to hit the monkey always

h - (vo*sin(theta)*t - 0.5gt^2) = 0.5gt^2

h = vo*sin(theta)*t

also, vo*cos(thata)*t = d

so, h = vo*sin(theta)d/vocos(theta)

h = tan(theta)*d

now, the bullet will always hit the monkey as long as it can cover the range d

so, v*cos(theta)*t = d

and vsin(theta)*t - 0.5gt^2 = 0

v*sinb(theta) = 0.5gt

t = 2v*sin(theta)/g

so, v*cos(theta)*2vsin(theta)/g = d

v > gd/sin(2*theta)

b. h = 10 m, d = 20 m

v > g*20/sin(2*theta)

also, 10/20 = tan(theta)

tehta = 26.56 deg

v > 245.25 m/s

c. if d = 0 then the molnkey will be hit for any velocity > = 0

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