. A kangaroo can jump over an object 2.50 m high Calculate its 7. leaves the gro
ID: 1865229 • Letter: #
Question
. A kangaroo can jump over an object 2.50 m high Calculate its 7. leaves the ground. A) 7.0 m/s B) 1.9 m/s C) 9.8 m/s D) 2.5 m/s A Ferris wheel has a radius of 10 m and makes one revolution in 10 weighing 640 N is sitting on one of the benches attached at thof the person the apparent weight (that is, the normal force exerted on her by the she passes through the lowest point of her motion? 8. f the wheel. What is bench) of the A) 640 N B) 382N C) 320N D) 898 N 9. The figure below shows a graph of the velocity of an object as a function of time. What is the displacement of the object from 0 s to 6.0s? time(s) A) +8.0 m B) +6.5 m C) +5.5 m D) -5.5 nmExplanation / Answer
7)
Initial velocity voy = 0
acceleration ay = -g = -9.8 m/s^2
displacement y = 2.5 m
final velocity vy = 0
vy^2 - voy^2 = 2*ay*y
0 - voy^2 = -2*9.8*2.5
voy = 7 m/s <<<----ANSWER
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8)
time period T = 10 s
angular velocity w = 2*pi/T = 0.63 /s
centripetal acceleration a = r*w^2 = 10*0.63^2 = 4
net force = Fapp - w
net force F = m*a
Fapp - W = m*a
Fapp = m*a + W
mass m = W/g = 640/9.8
Fapp = 64*4 + 640 = 898 N
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9)
displacement = area under the graph
displacement = area of trapezium ( 0s to 5s) + area of triangle( 5s to 6s)
displacement = -(5+1)/2*2 + 0.5*(6-5)*1 = -5.5 m <<<--------ANSWER
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