Answer all parts for 100% feedback !!! (3%) Problem 29: Unpolarized light of int

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Answer all parts for 100% feedback !!!

(3%) Problem 29: Unpolarized light of intensity 1,-750 W mis incident upon two polarizers. After passing through both polarizers the intensity is 2- 220 W/m* Randomized Variables o750 W/m2 2-220 Wm2 ©theexpertta.com 33% Part (a) What is the intensity of the light after it passes through the first polarizer in w m2, Grade Summa Deductions Potential ry 0% 100% cos0 tanO ( acosO Submissions Attempts remaining: 35 (5% per attempt) detailed view Sin cotana asin0a atan acotan sinhO cosh0 tanh cotanhO END Degrees Radians DELI CLEAR Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: 2 Feedback: 2% deduction per feedback là 33% Part (b) Write an equation for the angle between the polarizers in terms of the initial (10) and final (12) intensities -? 33% Part (c) Find the angle between the polarizers in degrees

Explanation / Answer

A) I1 = Io/2 = 750/2 = 375 W/m^2

B)I1 = Io/2

I2 = I1 cos^2(theta)

I2 = (Io/2) cos^2(theta)

Cos(theta) = sqrt (2*I2/Io)

Theta = cos-1 sqrt(2*I2 / Io)

C) Theta = cos-1 sqrt (2*220/750) = 40 degree

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