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please I need help with number one. ignore my notes please show all work. I am t

ID: 186477 • Letter: P

Question

please I need help with number one.
ignore my notes
please show all work. I am trying to understand everything

Teradiance at depth Z nce Loe Homework 1 Tnital irra Light Attenvation in Imole 1.) Light in Monterey Canyon. ° Photo Assume the following Ttenuaton oeFti cien Extinction coefficient for the upper 100 m = 0.15 m Extinction coefficient for deep water (100 m to the bottom)-0.06 m-1 nction Daily irradiance 40 Einsteins m2 d Color is unimportant (a simplification for the sake of the general problem) What is the photon flux rate at a depth of 1000 m in the canyon (photons m2 d)? What is the length of time that lapses between the arrival of each photon for any given square meter at that depth (1000 m)? 2. Biologists wish to set up a simulated in situ incubation in a shipboard incubator that has ponding to 100%, 55%, 30%, 10% and 1% of surface light-attenuated chambers corres irradiance. They determine that the Secchi Disk reading is 35 m. Calculate the depths to

Explanation / Answer

Ans 1. Photon flux rate can be calculated as number of photons per unit area .

the number of photons Np can be calculated as

Np = Irradiance (E)/ Energy of photon(h.c)

now irradiance is power of photon on given area per day.It is dependent on extinction coeeficient (K). Extinction coeeficient is amount of photon that is absorbed per area.

E and K are related by formula

I = I0 * e-kL

where I in actual irradiance at the depth

I0 is Initial irradiance

L is depth.

So now K is given for upper 100m and for deep water

so first we need to calculate I for upper 100 m

I = 40* e-0.15*100

I=12.24*10-6

then for next I we need to take I0 as 12.24*10-6