W WileyPLUS x WileyPLUS ×?[sh University of South Alabama ?UA syll-PH201-Sum18.d
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W WileyPLUS x WileyPLUS ×?[sh University of South Alabama ?UA syll-PH201-Sum18.dvi Ahmed × XNew Tab CSecure https://edugen.wileyplus.com/edugen/student/mainfr.uni WileyPLUS Halliday, Fundamentals of Physics, 10 Calculus-based Physics I ⅈ (PH 201-202) Home Read, Study & Practice Gradebook ORION Downloadable eTextbook Assignment> Open Assignment FULL SCREENPRINTER VERSIONBACK NEXT ASSIGNMENT RESOURCES Chapter 11, Problem 023 W1 Your answer is partially correct. Try again. hapter1 Chapter 11, Problem Chapter 11, Problem Chapter 11 Probiom Chapter 11, Problem Chapter 11, Problem Chapter 11 Probiom Chapter 11, Problem Force F 7.04 N 6.91 N k acts on a pebble with position vector r = 7.75 m j 5.09 m k relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (6.41 m, 0, 8.33 m)? (a) Numbe39.4475 T48.6464 54.56 Units Units Click if you would like to Show Work for this question: Open Show Work LINK TO TEXT Question Attempts: 3 of 6 used SAVE FOR LATER SUBMIT ANSWER Version 4.24.7.7Explanation / Answer
a)
About the origin
r will be same.
So, torque is
=r*F
=(7.75j-5.09k)*(7.04i-6.91k)
=(-54.56k-53.5525i-35.8336j)N-m
b)
r will be,
r=(7.75j-5.09k)-(6.41i-8.33k)
r=-6.41i+7.75j+3.24k
Now torque will be,
=r*F
=(-6.41i+7.75j+3.24k)*(7.04i-6.91k)
=(-53.5525i-21.4835j-54.56k)N-m
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