A baseball outfielder throws a 0.15 kg baseball at a speed of 40 m/s and an init

Question

A baseball outfielder throws a 0.15 kg baseball at a speed of 40 m/s and an initial angle of 30. What is the kinetic energy of the baseball at the highest point of its trajectory? 1. When a 1.0 gram rubber band with is lifted to a height of 1 m, stretched 10 cm and shot exactly horizontally, it flies 2.25 m before it hits the ground. If the rubber band were lifted to 1 meter again and stretched 10 cm as well, but this time pointed vertically, what maximum height would it reach (relative to the ground)? 2. An object with a mass of 40 kg is lifted 10 m up in the air and released. Find out how much gravitational potential energy the object has, then determine how fast it will be traveling just before it hits the ground. 3.

Explanation / Answer

1.

We know that kinetic energy is

KE= 0.5mv 2

Where v is there net velocity at any point.

Now, at the heighest point, only the horizontal velocity will remain so,

v=40cos30

So KE=0.5*0.15*(40cos30)2

=90J

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