Motion Detector Force Sensor Elastic cord THEORY 1. Give the formula for an impu

Question

Motion Detector Force Sensor Elastic cord THEORY 1. Give the formula for an impulse in terms of force: Force xtime FAt Give the formula for an impulse in terms of momentum: - 2. In a car collision, the driver's body must change speed from a high value to zero. Whether the change occurs quickly or slowly, is the change in momentum the same or different? SAME Is the time the same or different? diffeent Is the force the same or different? drfferet Given those answers, explain how hitting ah airbag is preferable tó hitting a steering wheel. 3. You throw a 400 g lump of clay at 10 m/s against a wall. The clay sticks to the wall. What is the impulse against the wall? You throw a 400 g rubber ball at 10 m/s against a wall, The ball rebounds at 8 m/s. What is the impulse against the wall? Given those answers, which object applies a greater force against the wall? Why? PROCEDURE in the data table.

Explanation / Answer

        Impulse= m*?v

2. Since vf=0 and vi> 0 remained constant values, there is no change in ?v.

When change ?v takes place quickly -> time ‘?t’ decreases and if change ?v takes place slowly ‘t’ in increases. Thus time is ‘different’.

Since F= m*?v/t -> ‘?t’ change ‘F’ changes. Thus force is ‘different’.

After hitting a airbag ?t increase and F decreases, so it safe our driving at high speed.

3. vi=10m/s, vf=0m/s, m=0.4g

Impulse= m*?v =0.4*(0-10) = -4.0 kg*m/s

vi=10m/s, vf=-8.0m/s, m=0.4g

Impulse= m*?v =0.4*(-8.0-10.0) = -7.2 kg*m/s

Rubber will apply a greater force than clay since impulse is greater and thus Force will be greater since Force= Impulse/?t

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