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MOLECULAR BIOLOGY Lab Prep Exercise B Transcription 3\' GGTATATTTTGGGCGGGCTGACTA

ID: 186387 • Letter: M

Question

MOLECULAR BIOLOGY Lab Prep Exercise B Transcription 3' GGTATATTTTGGGCGGGCTGACTAGTACGATCGTTCGACTCTTCGGATI 5 5 CCATATAAAACCCGCCCGACTGATCATGCTAGCAAGCTGAGAAGCCTAA 3 tanschption Stat point tormtination sequence write the sequence for the RNA strand, from 5, to 3". The top strand is the template strand and the bottom strand is the coding strand. (Tip: Remember that RNA uses Uracil (U) instead of Thymine (T)!) (Note: to keep things simple, we will skip the RNA processing steps in this lab-prep exercise). (Tip: If you did this properly, your RNA strand should be shorter than the DNA strand above) Translation Using the table on page 51, translate the mRNA from 5, to 3,, and write down the amino acids of the resulting polypeptide in the order that they are added during translation. (Hint: there are only 4 amino acids, if you use the start and stop codons properly) CHALLENGE: For more practice, try repeating the questions above using the bottom strand of DNA as your template strand, and transcribing that entire strand. Will a polypeptide be made? What problem occurs during translation? (i.e., what is missing?)

Explanation / Answer

mRNA sequence is:-

5'-CCAUAUAAAACCCGCCCGACUGAUC AUG CUG CAA GCU UGA GAA GCC UAA -3'

To make U understand i have put spaces afer start codon for translation

AUG is start codon and UGA is stop codon

So our peptide chain is

5'-Methionine-leucine-glutamine-alanine-3'