please give explaination! problem 4 part (ii) A fireboat pump delivers water to
ID: 1863282 • Letter: P
Question
please give explaination! problem 4 part (ii)
A fireboat pump delivers water to a vertical nozzle with a 3:1 diameter ratio, as in the figure above. If friction is neglected and the flow rate is 400 gal/min, how high will the outlet water jet rise in m? A fireboat pump delivers water from a static reservoir as in the figure above. If duct and nozzle friction head losses are 0.1 m, the flow rate is 400 gal/min and the pressure difference across the pump is 25 kPa, what power in kW is delivered to the water by the pump?Explanation / Answer
In the first question flow rate is 400 gal/min at (1)...So, you just need to ignore the pump and apply bernoulli's equation and continuity equation to obtain how high the water goes...
In the second part of question the flow rate is again 400 gal/min at (1)....But this time you have to evaluate the power delivered by the pump to lift the water from reservoir to point (1)...The static reservoir is the water at the bottom...This study comes under pipe and duct flows where you need the friction head loss and the pump pressure difference to obtain the power from the pump equation (An equation obtained by modifying bernoulli's equation)...I suggest that if you do not know how to solve the second part, get hold of any standard fluid mechanics book and study the part under pipe and duct flows....You will then easily solve the problem as it is very basic one...
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