The wad of clay of mass m = 0.22 kg is initially moving with a horizontal veloci

Question

The wad of clay of mass m = 0.22 kg is initially moving with a horizontal velocity v1 = 5.6 m/s when it strikes and sticks to the initially stationary uniform slender bar of mass M = 3.8 kg and length L = 2.04 m. Determine the final angular velocity of the combined body and the x-component of the linear impulse applied to the body by the pivot O during the impact. The angular velocity is positive if counterclockwise, negative if clockwise. The impulse is positive if to the right, negative if to the left.

The wad of clay of mass m = 0.22 kg is initially moving with a horizontal velocity v1 = 5.6 m/s when it strikes and sticks to the initially stationary uniform slender bar of mass M = 3.8 kg and length L = 2.04 m. Determine the final angular velocity of the combined body and the x-component of the linear impulse applied to the body by the pivot 0 during the impact. The angular velocity is positive if counterclockwise, negative if clockwise. The impulse is positive if to the right, negative if to the left. Answers: w2 = rad/s OxDeltat = N.s

Explanation / Answer

w2 = (3*m*v1) / [(M+m)L]...Counter Clockwise

Ox delta t = {M / [2(M+m)]} m*v1...right

I will post solution steps when I figure them out myself.

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