A downward force of 98 N acts on the free end of the illustrated pulley. m A = 4

Question

A downward force of 98 N acts on the free end of the illustrated pulley. mA = 47 kg, What is block A

A downward force of 98 N acts on the free end of the illustrated pulley. mA = 47 kg, What is block A's acceleration? Assume that all straight portions of the rope are oriented vertically. The pulleys and ropes are massless. Take the positive direction of motion to be downward. The minus sign in this instance means the block moves upward, not downward. Using the fact that the tension in the rope must remain constant in all sections of the rope, calculate the total force that the rope exerts on pulley B. Determine the net force acting on block A. Using Newton's 2nd law, formulate the equation of motion for block A and solve for its acceleration.

Explanation / Answer

by force balancing

98=(m*g)+(m*a)

by using this

98=(47*9.8)+(47*a)

a=-7.71 m^2/sec

a= 7.71 m^2/sec upward

net force on bolck A= (m*g)-(m*a)+98N

= 0.23N

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