a cylindrical tank is filled with water at by a pump that produces an absolute p
ID: 1860405 • Letter: A
Question
a cylindrical tank is filled with water at by a pump that produces an absolute pressure of 150kpa at the inlet. at the instant shown below, the air pressure is 100 kPa and H = 25cm. If the air is compressed isothermally, what will H be when the flow ceases?
Explanation / Answer
The flow will cease when pressure at inlet will become same as water pressure
Total height of tank = 75 + 25 = 100 cm = 1m
At H pressure equals
since temprature remains constant
Pi*Vi = Pf*Vf
Pi = initial air pressure
Pf = Final air pressure
Since cross section of tank is constant taking H in meters
=> Pi*0.75 = Pf*(1-H)
=> 100*1000*0.75 = Pf*(1-H) --------- 1
also
at inlet water pressure in final case
=> Pf + pgH = 150 kPa
=> Pf + 1000*9.81*H = 150k
Putting Pf from 1
=> 100*1000*0.75/(1-H) + 1000*9.81*H = 150k
=> DIviding by 1000
=> 75/(1-H) + 9.81*H = 150
=> 75 + 9.81*H - 9.81*H^2 = 150-150H
=> 9.81*H^2 - 159.81*H + 75 = 0
=> H = 15.81 & 0.484
Since Tanks Height is 1m so 15.81 is not possible
so H = 0.484 m = 48.4 cm
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