a contestant in a winter games event pushes a 53.0 -kg rock across a frozen lake

Question

a contestant in a winter games event pushes a 53.0 -kg rock across a frozen lake with a force of 25 N at 22 degrees below, and it the horizontal as show in figure (a) moves with an acceleration of 0.44 m/s^2 to the right

a) what is the normal force exerted by the l;ake surface on the rock?

b) Instead of pushing on the rock, the consestant now pulls on it with a rope over his shoulder at the same anglew above the horizontal as in part (a). See figure (b) above. Now what is the normal force exerted by the lake surface on the rock?

Explanation / Answer

Here ,

a)

let the normal force is N

N = mg + F * sin(22)

N = 53 * 9.8 + 25 * sin(22)

N = 528.8 N

normal force by the lake surface is 528.8 N

b)

for pulling the rope

N = mg - F * sin(22)

N = 53 * 9.8 - 25 * sin(22)

N = 510.0 N

normal force by the lake surface is 510.0 N

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