1. What is the shortest amount of time (in minutes) that it would take this pump

Question

1. What is the shortest amount of time (in minutes) that it would take this pump to fill a 24 gallon tank located

10 feet higher than the pump? Note: Remember that you calculated head height as part of the analysis

2. What is the maximum velocity (ft/sec) reached by the water traveling in the tubes? Note: the inner diameter

of the tubes is 3/4-inch, therefore the cross-sectional area of the tube can be determined.

3. If you were designing a sprinkler system that required a minimum of 30% efficiency, could this pump be

used? Why or why not?

4. If you ran this pump for 60 hours a month at maximum efficiency how much would it cost to run the pump

for the month? (you must make an assumption on the cost of electricity.)

rpm (RPMs) Watts (W) Pressure difference (V) Pressure difference (psi) Pressure Head (ft) Flowrate (GPM) Pressure Difference(Pa) flow rate (m^3/s) Power out (W) n 463.7 32 0.348 1.7392692 4.013698154 1.74 11996.60931 0.000109777 1.316951342 0.041154729 500.2 41 0.306 1.5293574 3.529286308 1.55 10548.74267 9.77898E-05 1.031559687 0.025159992 545 40 0.563 2.8138177 6.493425462 1.72 19408.30759 0.000108515 2.10609559 0.05265239 623.7 52 0.645 3.2236455 7.439181923 1.95 22235.09484 0.000123026 2.735492718 0.052605629 726.7 63 0.663 3.3136077 7.646787 2.29 22855.60911 0.000144477 3.302100201 0.052414289 803.2 77 0.826 4.1282654 9.526766308 2.51 28474.7106 0.000158356 4.509153354 0.058560433 909.8 101 1.013 5.0628727 11.68355238 2.79 34921.16445 0.000176022 6.146882133 0.060860219 1009 124 1.21 6.047459 13.95567462 3.11 41712.34845 0.000196211 8.184402819 0.066003249 1107 159 1.371 6.8521209 15.81258669 3.34 47262.50391 0.000210721 9.959216158 0.06263658 1153 162 1.518 7.5868122 17.50802815 3.39 52330.03715 0.000213876 11.19212899 0.069087216 1304 217 1.883 9.4110457 21.71779777 3.57 64912.68772 0.000225232 14.62041745 0.067375196 1401 275 2.103 10.5105837 24.25519315 3.86 72496.75107 0.000243528 17.65500376 0.064200014 1470 333 2.177 10.8804283 25.10868069 3.88 75047.7542 0.00024479 18.37094054 0.05516799 1601 382 2.163 10.8104577 24.94721008 3.86 74565.13199 0.000243528 18.15871285 0.047535898 1752 467 2.172 10.8554388 25.05101262 3.9 74875.38912 0.000246052 18.42322537 0.039450161

Explanation / Answer

a) Shortest time period = Volume of water required / Maximum flow rate = 24 / 3.9 = 6.1538 minutes

b) Maximum velocity = Maximum flow rate / Area of pipe

Max flow rate = 3.9 GPM = 0.521 feet^3 per minute = 8.683*10^-3 ft^3/s

Maximum velocity = 8.683*10^-3 /(pi/4*((3/4)/12)^2) = 2.83 ft / s

c) Most likely not. Because the maximum efficiency of pump is 6.9 % which is lot less than 30

d) Let power charge be $1 per KWhour

Max efficiency is at 11.19 W

Therefore Power charges for 60 hours = 11.19*60 / 1000 = 0.6714 $

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.