The density of liquid water at 25 C is 997 kg/m3 and the specific gravity of sol

Question

The density of liquid water at 25 C is 997 kg/m3 and the specific gravity of solid water (ice) at 0 C is 0.98. 100 kg of liquid water at 25 C and 50 kg of ice at 0 C are placed in an isolated container. Find: 1. the initial volume of the liquid-ice mixture, in m3, 2. the volume after all the ice is melted, in m3, 3. will the temperature of the liquid water increase or decrease? Why?

Explanation / Answer

specific gravity of solid water = .98 => density of ice or solid water = 980 kg/m3 volume = mass/density so, volume of liquid water = 100/997 m3 volume of solid water = 50/980 m3 total initial volume = 100/997 + 50/980 =0.15132 m3 part 2 for volume after all the ice melted u will have to find out the temp for which u will need some values like heat of fusion, specific heat of water, specific heat of ice after finding out final temperature u will have to find out density at that temp and again using total mass i.e 150 kg u will have to find volume if on the other hand we assume that density doesnt change much and it is still 997kg/m3 for water then we can find out volume= 150/997 =0.15045 m3 part 3 temperature of liquid water will decrease let me make u able to visualize it what happens when u put ice in water and all ice melts definitely temperature decrease its because ice takes some heat from water in order to melt and then increases its temperature and at the same time temperature of water decreases because it is giving heat to ice and water which is melting from ice when temperature of all the things become same this process stops and final temperature is lower than temperature of hotter body and higher than temperature of colder body

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