(c) (One-quadrant analog divider) For the circuit shown in Figure P5.47c, with V
ID: 1847348 • Letter: #
Question
(c) (One-quadrant analog divider) For the circuit shown in Figure P5.47c, with Vx,
Vz, and Vr being of positive polarity, show that the following relationship is obtained:
Vo = (Vx/Vz)(Vr)(R4R0/R1R2)
Why is this circuit called a one-quadrant divider?
(d) (Square-rooting circuit) To produce a square-rooting circuit, Vz in the divider circuit
(Figure P5.47c) is connected to Vo such that Vz = Vo. Show that Vo will now become proportional
to the square root of Vx as given by
Vo = sqrt(VxVrRoR4 / R1R2)
If all resistors are equal and Vr = +10V, find Vo
(Ans.: Vo = sqrt(10Vx) show all work
Explanation / Answer
C)
See his notes.
From Part A) (I1)(I2) = (I3)(I4)
From B) I1, I2, & I4 are a VGND b/c of the internals of the IC and I4 is a VGND b/c of the OpAmp.
So, I1 = VX/R1, I2 = VR/R2, I4 = V2/R4, & I3=Vo/R0
VXVR/R1R2 = VoVZ/R0R4
Solving for Vo: Vo = VXVR/VZ(R0R4/R1/R2)
D) With VZ = Vo, substitute into the answer of C)
See you in class tomorrow brah.
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