The open loop gain (Gd) of an amplifier is normally very large. In case there ar
ID: 1845784 • Letter: T
Question
The open loop gain (Gd) of an amplifier is normally very large. In case there are modifying inputs, this open loop gain can change significantly. On the other hand, the feedback component consumes less power and it is less subjected to the interference from the modifying inputs. Let's start by assuming open loop gain Gd= 104, feedback factor Hf= 0.1. Calculate the close loop gain A = y/xd in Fig. 2. Now if Gd is reduced by 10%, what is the corresponding decrease in A? More formally, desensitivity factor is defined as: find function f explicitly.Explanation / Answer
Close loop Gain
= Gd/(1 + Gd*Hf)
= 10000/(1 + 1000)
= 9.99
If Gd is reduced by 10%, Gd = 0.9(Actual Gd)
Thus, New A = 9000/(1 + 900) = 9.988
Now, A = G/(1 + GH)
dA/dG = 1/(1+GH)^2
Desensitivity
= dA/dG * G/A
= 1/(1+GH)^2 * (1+GH)/
= 1/(1+GH)
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.