An 80kg bungee jumper times one end of an elastic rope with stiffness 2000 N/m t

Question

An 80kg bungee jumper times one end of an elastic rope with stiffness 2000 N/m to the bridge and the other to himself. He jumps from the bridge. Assuming when he reaches his static equilibrium position his velocity is 35 m/s, determine The natural frequency of the vibratory motion of the jumper about his static equilibrium position The vibratory motion of the vibratory motion of the jumper about his static equilibrium position (in other words, his position versus time). No lost of energy is assumed. Sketch his position versus time.

Explanation / Answer

The answer of following question is as follows.

The maximum of this vibratory link is 78 hertz.

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