Given that your child\'s weight is 50 Ibf (222 N) and the Power Wheels Wild Thin
ID: 1842321 • Letter: G
Question
Given that your child's weight is 50 Ibf (222 N) and the Power Wheels Wild Thing^TM also weighs 222N, and that the Wild Thing^TM tires are 30.5 cm diameter, and that the 12 V battery has a capacity of 9 A-hr you can determine the maximum distance traveled on a single battery chaise. Report your answer in meters. Do so by assuming that there are no frictional, resistive, or other losses and that the battery/electric motor combination produces exactly the torque required to move your child in the Wild Thing^TM forward. You may assume that the coefficient of friction between the ground and wheels is 1.Explanation / Answer
ANS:3.78 Kilometers
the vehicle is run by an electric motor.
average walking speed of humans is 6 km / hour. so assume the vehicle also moves in that speed.
6 km = 6000 meters: dia of wheel = .305 meters: therefore rpm = 6000m/.305m/60mins = 327 rpm (wheel and motor)
torque= force * radius : 444N* .0125 m = 5NM (torque)
power of motor = (2*pi*N*T)/60
substitute t=5NM; N= 327 rpm
Power = 171 WATTS
total power of battery =V*I : 12v *9ah = 108 Watts
total stand by time = 108/171 = 0.63 hours
distance crossed in 1 hr = 6 km : there fore distance crossed in 0.63 hours is 3.78 hours
ANS:3.78 Kilometers
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