Same stick and same box. Now compare how mu Ch work is done by the force in each

Question

Same stick and same box. Now compare how mu Ch work is done by the force in each case. Assume that the force acts with the same strength, for the same brief amount of time. (a) It's the same amount of work in each case, because the forces act for the same amount of time. (b) It's the same amount of work in each case, because the forces act through the same distance. (c) The force on the box does more work, because the box is harder to pull. (d) The force on the stick does more work, because it acts through a greater distance. (e) There's not enough information to say: we need to know the moments of inertia for the box and the stick. (f) none of these choices are correct.

Explanation / Answer

Work done = Force*distance travelled

W = F*s

option A is wrong because work does not depend on time.

option C is also wrong because in the question it is given that the force(pull) is same.

option E is wrong because we don't need moment of inertia to calculate work.

Now, I think there is some information missing, because in the question it is given that "in each case", but there is no case given. So let me know if cases are given.

Otherwise work will be same if travelled distance is same, but as stick is lighter than box and force applied is same, so stick will travel more, which means work done on stick will be greater than work done on box.

Correct option is D

Comment below if you have any doubt.

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