FULL SCREEN SSIGHMENT RESOURCES ce CensnThe current Chaer 30, Problem 046 ts n s

Question

FULL SCREEN SSIGHMENT RESOURCES ce CensnThe current Chaer 30, Problem 046 ts n srThe oater. rdlem2 ms to 5 ms, and (c) 5 ms to 6 ms. (Ignore the behavior at the ends of the intervals.) The current i through a 5.3 H inductor varies with time t as shown by the graph of the figure. The inductor has a resistance of 18 . Find the magnitude of the induced emf during the time intervals (a) 0 to 2 ms; (b) 202 054 Review Score Obiective (a) Number (b) Number (e) Number Click if you would like to Show Work for this questions Open Show Work Units Units Units Question Attempts: 0 of 10 used savtPO"LATER MapleNet Copyright © 2000, 2016 by John wiey & Sons, Inc. or related compares. Arights reserved.

Explanation / Answer

flux = Li

induced emf = rate of change of flux = d(flux)/dt

e = L di/dt

(a) for t = 0 to 2 ms

e = 5.3 * ( 7 / 2x10^-3) = 18550 Volt

(b) for t = 2 to 5ms

e = 5.3 * (5 - 7) /( 3 x 10^-3) = 3533.3 volt

(c) e = 5.3 * 5 / (1 x 10^-3) = 26500 volt

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