FULL NEXT Question 8 A 1450-N uniform beam is attached to a vertical Using the d
ID: 1260282 • Letter: F
Question
Explanation / Answer
net torque = 0
T*sin80*L = W1*L/2*cos30 + W2*L*cos30
T*0.985 = (1540*0.5*0.866)+(1960*0.866)
a) T = 2400 N <_--------answer
b) along horizantal
Fx - T*cos50 = 0
Fx = T8cos50 = 1542.7 N <_--------answer
c) along vertical
T*sin50 + Fy = W1 + W2
Fy = 1661.5 N <_--------answer
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