A bead with a mass of 0.055 g and a charge of 10 nC is free to slide on a vertic

Question

A bead with a mass of 0.055 g and a charge of 10 nC is free to slide on a vertical rod. At the base of the rod is a fixed 20 nC charge.
Part A In equilibrium, at what height above the fixed charge does the bead rest? A bead with a mass of 0.055 g and a charge of 10 nC is free to slide on a vertical rod. At the base of the rod is a fixed 20 nC charge.
Part A In equilibrium, at what height above the fixed charge does the bead rest? A bead with a mass of 0.055 g and a charge of 10 nC is free to slide on a vertical rod. At the base of the rod is a fixed 20 nC charge.
Part A In equilibrium, at what height above the fixed charge does the bead rest?

Explanation / Answer

the electric force = weight

kq1q2/r^2 = mg

9*10^9*10*10^-9*20*10^-9 / r^2 = 0.055*10^-3*9.8

r = 0.0577 m

the height above the fixed charge = 5.77 cm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.