A mass spectrometer employs a magnetic field of 0.06T to deflect singly lithium

Question

A mass spectrometer employs a magnetic field of 0.06T to deflect singly lithium ions of mass 1.16 x10^-26?kh and charge 1.6x10^-19 coul, moving at a rate of 1.05 x10^5 mls perpendicular to the magnetic field. Calculate the radius of curvature to the lithium ions. A mass spectrometer employs a magnetic field of 0.06T to deflect singly lithium ions of mass 1.16 x10^-26?kh and charge 1.6x10^-19 coul, moving at a rate of 1.05 x10^5 mls perpendicular to the magnetic field. Calculate the radius of curvature to the lithium ions.

Explanation / Answer

magnetic field B= 0.06T

mass of singly lithium ions m =1.16 x10-26kg

charge q =1.6x10 -19 coul

Speed v = 1.05 x10 5 mls

the radius of curvature to the lithium ions r = ?

In magnetic field , Bvq = mv 2/ r

                            Bq = mv/r

From this r = mv /Bq

                 =(1.16x10 -26)(1.05x10 5) /(0.06 x1.6 x10 -19 )

                 = 0.126875 m

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