A mass of 7 kg lies on a horizontal surface with friction. The coefficient of st

Question

A mass of 7 kg lies on a horizontal surface with friction. The coefficient of static friction is 1.3. One force is applied to it in the -y direction as well. On earth, it requires some force applied in the +x direction to begin to move the mass. On some other planet where the mass of the planet is a factor of 11.4 larger than the mass of the earth and the radius of the planet is a factor of 2.1 larger than the radius of the earth, if the same mass is placed on the same horizontal surface with the same force pushing it down in the -y direction, how much more force is required to begin to move the mass in Newtons? 2 FI

Explanation / Answer

u = 1.3

g = G M / R^2

g' = G M' / R'^2 = G M / R^2 (11.4 / 2.1^2) = 2.585 g

g' = 23.4 m/s^2

On earth, N = F1 + m g

F2 - u N = 0

F2 = u (F1 + m g )

on planet. F' = u (F1 + m g') = u F1 + u m (2.58 g)

F' = u (F1 + m g ) + 1.58 u m g

F2' = F2 + 141 N

So now force required in horizontal is more than 141 N .

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