**The First post I did somehow deleted the picture and so I wasn\'t sure if the

Question

**The First post I did somehow deleted the picture and so I wasn't sure if the answer that was posted for me was correct since she/he did not include anything about oil.**

The gate AB is a 260 kg rectangular steel plate that is 1.5 m high and 1.1 m wide that is used to close adischarge outlet at the bottom of an oil tank. The gate is hinged at B. As a result of condensation inthe tank, there is fresh water at the bottom of the tank. a. Find the minimum moment M that can be applied at B to keep the gate closed. b. Sketch the shear diagram for AB and provide the value of the shear at local maxima and minima. So for part "a", The answer my professor gave me was 18 kNm. I didn't get anything close to that. Would be much appreciated if someone could show me the steps (step by step). Here is what I did though:

Water:

R(1) = (P/2)(9.81)(.9*1.1) = 4.37 kN

R1 @ 1.2m from B (1.5m - (.9/3))

Oil: Same equation as P(av) so (.9)(9.81)(1.5) = 13.24 kPa

R(2)=(P)(9.81)(.6*1.1) = 85.72 kN

R2 @ .3m from B (1.5-.9)/2

Moment: Now you do Sum of Moment about B = 0 0 = M - (R1*1.2) - (R2*.3) M = (R1*1.2)+(R2*.3) M = 30.97 kNm Am I suppose to do (P/2) for the oil as well? I drew a horizontal line from B as the cut off point of the oil. Is the R2 distribution suppose to a triangle shape as well? If I do (P/2) for the oil, my answer becomes 18.1 kNm, but I'm not sure if that is 100% correct. Thanks.

Explanation / Answer

18KN

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