- Suppose that in a senior college class of 500 students it is found that 210 sm

Question

- Suppose that in a senior college class of 500 students it is found that 210 smoke, 258 drink alcoholic beverages, 216 eat between meals, 122 smoke and drink alcoholic beverages, 83 eat between meals and drink alcoholic beverages, 97 smoke and eat between meals, and 62 engage in all three of these bad health practices. If a member of this senior class is selected at random, find the probability that the student, (a) Smokes but does not drink alcoholic beverages. (b) Eats between meals and drinks alcoholic beverages but does not smoke. (c) Neither smokes nor eats between meals.

Explanation / Answer

We generally do not answer the questions of those who are having low rating. You are having a rating of "95%". Please rate all answers and improve your rating. Even if you find the answers are incorrect, rate them as not helpful. But do rate them for the good of both of us. Thanks!! Coming to the problem P(A) = 210, P(B) = 258, P(C) = 216 P(A intersection B) = 122, P(B intersection C) = 83, P(C intersection A) = 97 P(A intersection B intersection C) = 62 P(AUBUC) = P(A)+P(B)+P(C)-P(A intersection B)-P(B intersection C)-P(C intersection A)+P(A intersection B intersection C) = 444 a)Probability that a student Smokes but does not drink alcoholic beverages = (210-122)/(500) = 0.176 b)Probability that a student Eats between meals and drinks alcoholic beverages but does not smoke = (444-210)/(500) = 0.468 c)Probability that a student Neither smokes nor eats between meals = (258-122-21)/500 = 0.23

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