- Point d= 3.2x10^7 m/s Two large parallel conducting plates have equal and oppo

Question

- Point d= 3.2x10^7 m/s

Two large parallel conducting plates have equal and opposite charges. The distance between the plates is 0.12 m. An electron is placed between the plates, and experiences a constant electrostatic force of 3.9times l0-15 N , at any point between the plates. Determine the magnitude of the electric field between the plates. Determine the potential difference between the plates. The electron is initially at rest at the surface of the negative plate, and released so that it accelerates through this potential difference, toward the positive plate. Determine the change in potential energy for the electron during this motion. Determine the speed of the electron just before it arrives at the other plate. (Use conservation of energy.)

Explanation / Answer

a) E = F/q = 3.9E-15/1.6E-19=24375 N/C

b) E = V/d

so V = Ed = 24375*0.12= 2925 V

c) dPE = q dV = -1.6E-19*2925=-4.68E-16 J

d) dPE + dKE = 0

so 1/2 mv^2 = dPE

0.5*9.11E-31*v^2 = 4.68E-16

v=3.2E7 m/s

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