I need a solution for all parts, please! Three-bar truss ABC (see figure) is con

Question

I need a solution for all parts, please!

Three-bar truss ABC (see figure) is constructed of steel pipes having a cross area A 3500 mm2 and a modules of elasticity E = 210 GPa. Member BC is of length L = 2.5 m, and the angle between members AC and AB is known to be 60 degree. Member AC length is b = 0.71L. Loads P = 185 kN and 2P = 370 kN act vertically and horizontally at joint C, as shown joints A And B are pinned supports. (Use the law of sines and law of cosines to find missing dimensions and angles in the figure.) Find the support reactions at joints A and B. Use horizontal reaction Bx as the redundant. What is the maximum permissible value of load variable P if the allowable normal stress in each truss member is 150 MPa? PROB. 2.1-14

Explanation / Answer

Steps to solve this problem First take truss as a whole to find the reaction forces at A and B. p is given =185 N . Bx=0 since it says " use the horizontal reaction Bx as the redundant " in question A so there are three unknowns Ax Ay By you can use summation of force along the x axis and yaxis and summation of moment equation at A to find the three unknown forces. Three unknowns three equations . b. All the members are two force members so the force is directed along the length. use equilibrium of each joint(pin) to calculate each force in the member. divide the force by the area which is equal to 3500 millimeter cube to find the stress. Repeat step A but now write the reaction forces at A and B and the forces along the members in terms of the force P. write a relation between the force p and the stress in each members . In the members with the highest streess subsitute the stress 150 MPA and calculate P

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