the steps of transcription and translation in the appropriate order 1-11. Some o
ID: 181930 • Letter: T
Question
the steps of transcription and translation in the appropriate order 1-11. Some options will not be sed. RNA polymerase binds to promoter region on DNA RNA polymerase stops adding bases when reaching the terminator region on DNA Introns are removed during splicing mRNA travels to ribosome in cytoplasm to begin translation Transcription bubble forms and DNA unwinds Formation of the primary RNA ('pre-mRNA") transcript is complete Exons are spliced together to form mRNA RNA polymorase adds complementary nucleotides as DNA code is read Exons are removed Introns are spliced together to form mRNA tRNA reaches stop codon Polypeptide is released tRNA reads mRNA in codons while carrying the corresponding amino acidsExplanation / Answer
1 - a
2 - e
3 - h
4 - b
5 - f
6 - c
7 - g
8 - d
9 -m
10 - k
11 - l
The RNA polymerase binds to the promoter region (a). Then it melts the DNA at the transcription start site to begin transcription (e). The polymerase then reads the DNA (gene) and adds complementary bases to form an RNA (h). The polymerase reads the terminator sequence (the DNA makes a hairpin structure) and stops (b). The pre-mRNA comes out of the transcription site and the post-transcriptional modification begins (f). The introns are removed in a process called splicing, and the exons are joined together (c, g). This process is coupled, which means, both these process occur simultaneously at one place. The mature mRNA then moves to cytoplasm to begin translation (d). There it binds to ribosome. The tRNAs, along with their amino-acids read the mRNA codon-by-codon (m). No tRNA will bind to a stop codon. Therefore, at a stop codon, translation ends (k). At the end, the polypeptide is released (l).
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