the solenoid\'s magetie the magnitude of the torque exerted on the loop rotate c
ID: 2039458 • Letter: T
Question
the solenoid's magetie the magnitude of the torque exerted on the loop rotate clockwise or counterclockwise in response to this torque? d) does the dipole 5. If the solenoid mentioned above is in the form of a cylinder which is 75 cm long and has a radius of 15 cm, what is its inductance? es from 5 A to zero in 10s, what is the magnitude of the in the center of the solenoid, which in real life 6. If the current in the solenoid decrease lenoid? (Ignore the wire induced emf in the so would also be affected.) Would t direction? his emf induce a curren t in the direction of the original current, or in the opposite 7. A uniform magnetic field with a strength of 0.01 T is pointing into the page of paper. Take a copper wire with a diameter of 1 mm and a length of L 0.75 m. .Form the wire into a square, as shown. Obviously a0 ao ao . Now begin pulling the left and right sides of the square at a constant speed ao square turns into a rectangle which completely closes up after 0.5s So for example, at t = 0.25 s, the rectangle looks like this, with , so that the a0.25??? and 0.25s 25s ao.25sExplanation / Answer
a) R = resistivity*length / area
R = 1.69e-8*0.75 / 7.85e-7
R = 0.016146 OHMS
b) at t = 0 , it is a square,
A = side*side
A = 0.1875*0.1875 = 0.0352 m2
c) Magnetic flux = BA
Magnetic flux = 0.01*0.0352
Magnetic flux = 3.52e-4 Tm2
d) We will consider t = 0.25 seconds.
A ( at t = 0.25) = 3L/8*1L/8
A = 0.28125*0.09375
A = 0.02637 m2
e) Flux = 0.01*0.02637
Flux = 2.64e-4 Tm2 ( As we can see flux has decreased as area decreased)
f) d(flux)/dt = d(BA) / dt
as B is constant, We have B dA/dt
Flux = B*(0.02637 - 0.0352 / 0.25)
Flux = 3.53e-4 Tm2 / s
g)
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