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Boundary work for a closed system is zero for a rigid boundary is equal to the a

ID: 1818554 • Letter: B

Question

Boundary work for a closed system is zero for a rigid boundary is equal to the area under the P-V diagram has a magnitude less than zero for a compression process All of the above None of the above. A frictionless piston-cylinder device contains 2 lbm of water vapor at 20 psia and 320 degree F. Heat is transferred to the water until the temperature reaches 500 degree F. If the piston is not attached to a shaft and its mass is constant, what is the amount of boundary work? 0 Btu 219.1 Btu 40.5 Btu -219.1 Btu Calculate the total work, in kJ, for the process 1-2-3 shown in the figure to the right. 231.25 kJ 981.25 kJ -81.25 kJ -231.25 kJ An apple with an average mass of 0.2 kg and average specific heat of 3.85 kJ/kg degree C is cooled from 22 degree C to 5 degree C. The amount of heat transferred from the apple is 11.2 kJ 65.4 kJ 17.7 kJ 13.1 kJ An ideal gas has a gas constant R = 0.3 kJ/kg.K and a constant-volume specific heat of 0.7 kJ/kg.K. If the gas is cooled from 280 degree C to 170 degree C, the enthalpy change is -77 kJ/kg -110 kJ/kg 33 kJ/kg -33 kJ/kg

Explanation / Answer

1.D
2.A (Because the Volume doesn't change hence Boundary Work=PdV =0)
3.A (Area under the curve)
4.D (mcT = 13.1 kJ)
5.B {Enthalpy Change = -CpT = -(R+Cv)T as Cp=R+Cv}

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