<p>Hey there,</p> <p>just have a question on specific heats Cp and Cv.</p> <p>So
ID: 1817078 • Letter: #
Question
<p>Hey there,</p><p>just have a question on specific heats Cp and Cv.</p>
<p>So far I understand they're separated by the universal gas constant, R (In this case, 8.314 / Molecular weight I'm assuming), and for incompressibles (liquids)<br />Cp=Cv.<br /><br />For all other cases though (Ideal gas behavior problems, see the second one posted), I have no idea how to use it and the book isn't the greatest in explaining them.<br /><br />Any help? Like if I had to find the work or heat with them?<br />obviously for constant volume, no work is done but how do you find the heat transfer?<br />Thank you! Here go some sample pictures of what I'm talking about (#2) and the work this girl did...<img class="mceBlock" src="https://s3.amazonaws.com/answer-board-image/6ef222ac-26c5-478d-9e88-c5e9b8fe2db0.jpeg" border="0" alt="uploaded image" /><img class="mceBlock" src="https://s3.amazonaws.com/answer-board-image/6e30280e-baac-410f-8cd1-f11cfa61f09e.jpeg" border="0" alt="uploaded image" /></p>
Explanation / Answer
your question isnt looking clear due to the faulty script and the uploaded image is also not displayed in the webpage But I understood that you need some clarity in finding heat transfer for a constant volume process And here goes the answer for your question........ heat transferred is sum of internal energy and work done dQ = du + dw for constant volume process, dw = 0 { since dv = 0 , Pdv = 0 and (Pdv = dW) } Hence it implies that the heat transfer is equal to the internal energy change and internal energy is a function of temperature Hence finding heat transfer solely depends on temperature If you know the temperature difference then dQ = m cv (t2 - t1) [since this is a constant volume process] for any other help please message me i will surely help you.. Also dont forget to rate this anwer..........
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