<p>Can someone give me the working problem AND the way to figure this out on the

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<p>Can someone give me the working problem AND the way to figure this out on the calulator, I am still struggling figuing this stuff out. THANKS IN ADVANCE!!!</p>
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<p>1. A newspaper conducted a statewide survey concerning the 1994 race for senator. The newspaper took a random sample ( assume it is an SRS ) of 1200 registered voters and found that 630 would vote for the Republican candidate.<br />Let p represent the proportion of registered voters in the state that would vote for the Republican candidate.<br />a. Give a 95% confidence interval for p. Indicate what the margin of error of the confidence interval is.</p>
<p><br />b. The Republican candidate claims that she has a clear majority based on this sample. You realize this is a perfect situation to conduct an hypothesis test. State the null and alternative hypotheses for an hypothesis test. Compute the Pvalue.</p>
<p><br />Explain what the P-value provides in the way of evidence either for or against the Republican&#8217;s claim. Is the test significant at the 5% level?</p>

Explanation / Answer

N= 1200 proportion = 630/1200 = .525, q=1-p=.475 95% confidence interval for p. margin of error of the confidence interval State the null and alternative hypotheses for an hypothesis test. Compute the Pvalue. Explain what the P-value provides i Is the test significant at the 5% level?

SE =sqrt( ( p q)/n) =sqrt( ( .525 .475)/1200) =.0144 z is 1.93, two tail margin of error ME is z times SE = 1.93 x .0144 = .028 Confidence Interval is: p + / - ME = .525-0.28 to .525 +0.28 = .497 to .553 So with 95% confidence we are not really sure he has a majority since the interval includes an area BELOW 50%

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