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A 10kg ball is dropped from aheight such that it hits a 15kg triangular block af

ID: 1815311 • Letter: A

Question

A 10kg ball is dropped from aheight such that it hits a 15kg triangular block after falling 5m.The triangular block sits atop a long 30kg rectangular block. Thesloped side of the triangular block forms a 30o degree angle with the horizontal. Thecoefficient of restitution between the triangular block and theball is 0.6. A coefficient of kinetic friction and coefficient ofstatic friction, k = 0.2 and s = 0.4 respectively, exist between thetriangular block and the rectangular block and between therectangular block and the ground.

Explanation / Answer

question is kinda weird but i'll do my best, a) using engery eq then the velocity of the ball would be2gh (then .6 times that value), the velocity at impact ibelive would be (.62gh)*cos 60 = vy andvx would be (.62gh)*sin 60 b) now it is a problem of summing forces and determing if theball forces the triangle to move Fs <=sN then use kN after you knowthat it moves that's all i can remember at the moment... help this gets you on the right track...
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